Uncategorized

Newton’s Laws and Making a Rocket Go

In about 1687, Isaac Newton came up with three laws:

1. An object at rest tends to stay at rest and an object in motion tends to stay in motion unless an external force acts upon it.
2. A force applied to an object is equivalent to its change in momentum. Most people think of this as being the formula F=ma, where F is the force (a vector, hence it is in bold, meaning that it has both magnitude and a direction, like up or down), m is the object’s mass (a scalar), and a is the object’s acceleration (another vector). Keep in mind that this is a simplification, though! Really, force is a change in momentum, which is the product of the object’s mass times its velocity. This will be discussed below.
3. For every action, there is an equal and opposite reaction.

The first law is describing something like cars accelerating and decelerating (for example). The second law is sort of a quantification of this – how much force you have to apply to make something accelerate and decelerate. Well, it is mass related. If the object is very big (a aircraft carrier, for example) it takes a LOT of force to accelerate it. If the object is small (a rabbit, for example) it can be accelerated very, very quickly. Newton’s third law is the law that is going to help us get into orbit. The classic example of this law in action is two skaters standing on ice. If they are about the same size, and they push off of each other, they both go backwards with about the same speed.

If you combine the second and third laws, you can envision what would happen if you had a very big skater and a very small skater push off each other – the big skater would not go backwards very fast, while the small skater would move backwards very fast. This is the heart and soul of rocketry!

It is sometimes hard to understand the last law in the world we live in. For example, if you push off of a brick wall, the wall doesn’t move backwards. If you push off the ground, the ground doesn’t move. This is really because the brick wall and the world are either too massive for a tiny force to really matter, or the force that you apply are absorbed in a way that you don’t really see. But, take it from me – the forces are really there and they really work. For example, take a very large car and put it on a very flat road in neutral with the parking break off. If you push on it, it will move. Very slowly, but it will move. If you put the parking break on, it won’t move. This is because you don’t have enough strength to overcome the frictional force that is keeping the car in place (neither do I).

Let’s take the example above with the big skater and little skater and generalize it to something that every American can relate too: guns! (Actually, I don’t own a gun, unless you count nail guns, then I own 4 of them!) If you take a big football player and have them fire a tiny gun, then they wouldn’t move backwards hardly at all, but the bullet would move out quite quickly.

Thinking about Newton’s second law, that says that a force has something to do with mass, we can understand this: The bullet has a tiny mass, so it moves forward quickly, while the football player has a huge mass, so he hardly moves at all.

We can describe this in terms of momentum, which is the product of the mass of an object and it’s velocity.  The bullet has a large velocity and small mass, while the football player has a large mass and small velocity.  Newton’s third law basically is saying that when the bullet leaves the gun, it has a certain momentum, therefore, the football player has to have exactly the same momentum in the opposite direction.

This, in essence, describes how a rocket works. The gas coming out of a rocket’s engine has a very small mass (compared to the rocket), but it is moving incredibly fast.  The rocket itself is HUGE, so it moves very slowly (at first).

After a minute or so, the rocket has expelled so much fuel, that the mass has decreased significantly, so that the mass of the rocket and the mass of stuff that is coming out are closer to equal, like this example:

In this case, the mass of the little girl is still much larger than the bazooka bullet, but the bullet is still moving very quickly, and therefore the girl moves backwards pretty quickly also.  The momentum of the girl and the momentum of the bullet have to be equal and opposite.

Next time, we will take a closer look at Newton’s Second Law and learn how to calculate thrust!

(Artwork done by Alan Ridley)

Uncategorized

Terminal Velocity and Drag

One of my favorite forces to think about is air resistance, or the drag force.  I like this force since it is very easy to relate to and it strongly affects the vast majority of people in ways that they probably don’t even realize. (Actually, as a cyclist, I hate this force most of the time, and very much like it whenever there is a tailwind…) And, it is critically important for rockets and space flight, too!

You probably have had some experience with wind resistance.  When the wind is blowing hard, you can feel the force of it.  When you are riding a bicycle, you can feel its effect.  When you are driving a car, you are affected by wind resistance.

Typically, we can think of wind resistance, or drag, as being a force that is applied to an object that is trying to move through a medium.  For example, if you are riding a bicycle, you feel drag from moving through the atmosphere. As you go faster and faster, you have to exert more and more energy to keep going. If there is a head wind (i.e., the wind is blowing opposite to the direction that you are moving, or into your face), you have to exert even more energy.  If there is a tail wind (i.e., the wind is blowing with you, or on your backside), then you exert less energy to go the same speed.

Mathematically, we can write the drag force as (sorry – math!):

F=-½ρΑCV²

ρ (rho) is the density of the medium that the object is traveling through (i.e., air). If this increases, then the force become harder to move through. For example, it is almost impossible to ride your bicycle through water, since the density of water is about 1000 times the density of air.  So, it is literally 1000 times harder to ride your bike in water, even with scuba gear on. Submarines have a top speed of about 30 MPH, while commercial jets have a top speed of about 600 MPH. It is because of the density of the medium they are traveling through.

A is the frontal area of the object that is moving through the medium.  The area is why it is much easier to ride a bicycle at fast speeds bent over, rather than sitting in an upright position. It is also why bigger cars tend to get worse gas milage than smaller cars, or adding things like racks on the top of your car will reduce your fuel efficiency.  Read this page for more car information!

C is the “drag coefficient”, which is sort of difficult to actually measure. It describes how easy it is for the air to flow around the object.  So, something that is more aerodynamic in shape (like an arrow or a wedge) has a much smaller drag coefficient than something that is flat (like a semi-truck) or shaped like a parachute.  You can also change the drag coefficient of an object by coating it with something special.  For example, modern cars are painted with special paints that help the air move more smoothly over the surface. Swimmers now wear body suits that allow the water to move across their bodies easier than their bare skin.  Fish are super slippery to allow them to have a very low drag coefficient in water.

V is the velocity of the object moving through the medium with respect to the medium. It is squared, which means that if you double the object’s speed, the force goes up by four times.  This is why a head wind and a tail wind make such a huge difference when biking. Even a small change in the relative velocity between your speed and the atmospheric speed will have a big difference in the amount of force you have to apply to move at your speed. It is also why flying from the west coast of the US to the east coast takes significantly less time than traveling from the east coast to the west coast – the jet stream is typically from west to east, so you have a tail wind in one direction and a head wind in the other.

One of my favorite subjects to discuss with respect to the drag force is terminal velocity, which is when the force of gravity balances the drag force.  The most common example of this is someone jumping out of an airplane. When a person jumps out of an airplane, gravity starts to pull them down towards the ground, and they accelerate.

Then, as the person gains speed, the drag force acts to reduce their acceleration (but they are still gaining speed!) As the person falls faster and faster, the drag force becomes larger and larger (because of the V term).  Eventually, at a certain speed, the drag force exactly equals (but is opposite to) the force of gravity.  This is terminal velocity.

I know that equations suck, but looking at the equation for terminal velocity gives some pretty interesting insights into some cool things. So, plug your nose and take a look:

In this equation, V is the terminal velocity, m is the mass of the object that is falling, g is gravity (we can think of this as just 10 for now), ρ is the density of the air, A is the area, and C is the drag coefficient.  So, what does this mean?

Well, if something is heavier (or more massive), it falls with a faster speed. If the object has a larger area, it falls slower.  If it is shaped like a parachute instead of a bullet (i.e., C is larger), it falls slower.  Finally, if the density of the air is larger (like water instead of air), the object falls slower (a bowling ball will fall about 30 times slower in water than in air.)

As the plot above shows, and the equation describes, if Dave falls with his toes down, he will fall faster than if he is spread eagle on his back. This is mainly because his area is increased being spread eagle.

Since Dave doesn’t have a parachute in this example, he will continue falling at a rate that is not conducive to survival. On the other hand, if he were to open a parachute, his area would increase dramatically and he would slow way down.

If you have heard of Galileo and the thought experiment of dropping a feather and a bowling ball off the top of a tower, you will know that physicists will say that they should hit the ground at the same time. That is only true if there is no air!  If there is air, they behave exactly as you expect: the feather “floats” to the ground, while the bowling ball plummets to the ground. If you want to see how the feather and bowling ball fall in air and in a vacuum, take a look at this video, which is awesome. Seriously, it is so cool.